Oscar: Cotto easier than Manny!!

[amat]

Assuming PAC and Cotto are of the same size (assuming they're both natural 147 boxers), who do you think the easier fight for Oscar?

OK forgive me for asking this, I'm afraid I'm taking the bait.

Why would anyone ever assume that Pac and Cotto are the same size?

So that we can evaluate the other factors (skills, speed, heart, stamina, etc.) in PAC and Cotto's arsenal that can possibly give problems to Hoya. Remember we will not factor the size here, assume PAC and Cotto are of same size.

OK, you mean match them up P4P or match them up as prospective ODLH opponents? Because if it's matching them up and comparing them for ODLH, then you can't assume they are the same size because they simply aren't.